232. Implement Queue using Stacks
Easy
Problem:
Implement a queue using a stack that supports the following operations.
Implement the MyQueue
class:
void push(int x)
Pushes element x to the back of the queue.int pop()
Removes the element from the front of the queue and returns it.int peek()
Returns the element at the front of the queue.boolean empty()
Returnstrue
if the queue is empty,false
otherwise.
Input
["MyQueue", "push", "push", "peek", "pop", "empty"]
[[], [1], [2], [], [], []]
Output
[null, null, null, 1, 1, false]
Explanation
MyQueue myQueue = new MyQueue();
myQueue.push(1); // queue is: [1]
myQueue.push(2); // queue is: [1, 2] (leftmost is front of the queue)
myQueue.peek(); // return 1
myQueue.pop(); // return 1, queue is [2]
myQueue.empty(); // return false
Notice: You must use only standard operations of a stack, which means only push to top
, peek/pop from top
, size
, and is empty
operations are valid.
Solution:
Use two stacks.
class MyQueue:
def __init__(self):
self.input = []
self.output = []
def push(self, x: int) -> None:
self.input.append(x)
def pop(self) -> int:
self.peek()
return self.output.pop()
def peek(self) -> int:
if not self.output:
while self.input:
self.output.append(self.input.pop())
return self.output[-1]
def empty(self) -> bool:
return self.input = [] and self.output == []
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